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on December 23, 2018

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LED-URI- 1168

URI Online Judge | 1168 LED Unknown Author Timelimit: 1 John wants to set up a panel containing different numbers of LEDs. He does not have many leds, he is not sure if he will be able to mount the desired number. Considering the configuration of the LEDs of the numbers below, make an algorithm that helps John to discover the number of LEDs needed to set the value. Input The input contains an integer N , (1 ≤ N ≤ 2000) corresponding to the number of test cases, followed by N lines, each line containing a number (1 ≤ V ≤ 10 100 ) corresponding to the value that John wants to set with the leds. Output For each test case, print one line containing the number of LEDs that John needs to set the desired value, followed by the word "leds". Input Sample Output Sample 3 115380 2819311 23456 27 leds 29 leds 25 leds Solution: #include<bits/stdc++.h> using namespace std; int main() { string s; int t,c,i,j; cin>&

Age in Days(URI Online Judge | 1020)

URI Online Judge | 1020 Age in Days Adapted by Neilor Tonin, URI Brazil Timelimit: 1 Read an integer value corresponding to a person's age (in days) and print it in years, months and days, followed by its respective message “ano(s)”, “mes(es)”, “dia(s)”. Note: only to facilitate the calculation, consider the whole year with 365 days and 30 days every month. In the cases of test there will never be a situation that allows 12 months and some days, like 360, 363 or 364. This is just an exercise for the purpose of testing simple mathematical reasoning. Input The input file contains 1 integer value. Output Print the output, like the following example. Input Sample Output Sample 400 1 ano(s) 1 mes(es) 5 dia(s) 800 2 ano(s) 2 mes(es) 10 dia(s) 30 0 ano(s) 1 mes(es) 0 dia(s) Solution: #include<bits/stdc++.h> using namespace std; int main() { int n,y,m,d,b; cin>>n; y=n/365; b=n%365; m=b/30; d=b%30; printf

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